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Proof step 117 from proof putarray-addarray-01 (previous step)

i ≤ j, 0 ≤ i, 0 ≤ j, n→i(# vals) + i < j ⊦ putArray(vals, r, i, addarray(r, ty, j, st)) = (addarray(r, ty, mklist(initial_value(ty), i→n(i)) + vals + mklist(initial_value(ty), i→n(j - i + n→i(# vals))), st)[r -- _length, intval(j)])

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 116:
j = i0 + i + n→i(# vals), i ≤ j, 0 ≤ i, 0 ≤ j, n→i(# vals) + i < j ⊦ putArray(vals, r, i, addarray(r, ty, j, st)) = (addarray(r, ty, mklist(initial_value(ty), i→n(i)) + vals + mklist(initial_value(ty), i→n(i0)), st)[r -- _length, intval(j)])

Rule argument

[speclemmaarg: ,i0 = i - j ↔ i = i0 + j ,[i, j, i0] → [j, i + n→i(# vals), i0] ,T ,int-abs , ,elim-sub ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPELIM : ⊦ i0 = i - j ↔ i = i0 + j])], [EXTRATERMS : (j, i + n→i(# vals), i0)]]