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Proof step 14 from proof putarray-addarray-01 (previous step)

0 ≤ i, 0 ≤ i0 + n→i(# vals), 0 ≤ i0 + i + n→i(# vals), 0 < i0 ⊦ r -- i1 ' ∈ addarray(r, ty, i0 + i + n→i(# vals), st) ∨ i ≤ i1 ∧ i1 < i + n→i(# vals) ↔ r -- i1 ' ∈ st ∨ ¬ i1 < 0 ∧ ¬ i + n→i(# vals) + i0 ≤ i1

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 9:
⊦ r ≠ r0 → (r -- sk ∈ addarray(r0, ty, i, st) ↔ r -- sk ∈ st)
Proof step 13:
¬ r ≠ r, 0 ≤ i, 0 ≤ i0 + n→i(# vals), 0 ≤ i0 + i + n→i(# vals), 0 < i0 ⊦ r -- i1 ' ∈ addarray(r, ty, i0 + i + n→i(# vals), st) ∨ i ≤ i1 ∧ i1 < i + n→i(# vals) ↔ r -- i1 ' ∈ st ∨ ¬ i1 < 0 ∧ ¬ i + n→i(# vals) + i0 ≤ i1

Rule argument

[crewrite-arg: in-1dim-01 , F , [st, i, ty, r0, sk, r] → [st, i0 + i + n→i(# vals), ty, r, i1 ', r] ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (st, i0 + i + n→i(# vals), ty, r, i1 ', r)]]