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Proof step 185 from proof putarray-addarray-01 (previous step)

i→n(i1 + i) = n + i→n(i) ∧ i→n(i) ≤ i→n(i1 + i), 0 ≤ i1, 0 ≤ i1 + i, 0 ≤ n→i(# vals) + i, 0 ≤ j, 0 ≤ i, i ≤ j, j ≤ n→i(# vals) + i, i1 < n→i(# vals), 0 < i + n→i(# vals) ⊦ vals = [], vals[i→n(i1)] = vals[n]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 184:
i→n(i1 + i) = n + i→n(i), 0 ≤ i1, 0 ≤ i1 + i, 0 ≤ n→i(# vals) + i, 0 ≤ j, 0 ≤ i, i ≤ j, j ≤ n→i(# vals) + i, i1 < n→i(# vals), 0 < i + n→i(# vals) ⊦ vals = [], vals[i→n(i1)] = vals[n]

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ i ≤ 0 ∧ 0 ≤ j → i ≤ j], [CSIMPSEQ : ⊦ i ≤ i + j ↔ 0 ≤ j], [CSIMPSEQ : ⊦ i + j = j + i], [CSIMPSEQ : ⊦ i + j + i0 = (i + j) + i0], [CSIMPSEQ : ⊦ 0 ≤ i ∧ 0 ≤ j → abs(i + j) = abs(i) + abs(j)], [CSIMPSEQ : ⊦ 0 ≤ i → abs(i) = i], [CSIMPSEQ : ⊦ i→n(i) ≤ i→n(j) ↔ abs(i) ≤ abs(j)])]]