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Proof step 190 from proof putarray-addarray-01 (previous step)

0 < i + n→i(# vals), 0 ≤ i0, i0 < i + n→i(# vals), j ≤ n→i(# vals) + i, i ≤ j, 0 ≤ i, 0 ≤ j, 0 ≤ n→i(# vals) + i, i0 < n→i(# vals) + i, i ≤ i0 ⊦ vals[i→n(i0 - i)] = (mklist(initial_value(ty), i→n(i)) + vals)[i→n(i0)], vals = []

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 189:
i0 = i1 + i, 0 < i + n→i(# vals), 0 ≤ i0, i0 < i + n→i(# vals), j ≤ n→i(# vals) + i, i ≤ j, 0 ≤ i, 0 ≤ j, 0 ≤ n→i(# vals) + i, i0 < n→i(# vals) + i, i ≤ i0 ⊦ vals[i→n(i1)] = (mklist(initial_value(ty), i→n(i)) + vals)[i→n(i0)], vals = []

Rule argument

[speclemmaarg: ,i0 = i - j ↔ i = i0 + j ,[i, j, i0] → [i0, i, i1] ,T ,int-abs , ,elim-sub ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPELIM : ⊦ i0 = i - j ↔ i = i0 + j])], [EXTRATERMS : (i0, i, i1)]]