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Proof step 223 from proof putarray-addarray-01 (previous step)

0 ≤ n→i(# vals) + i, 0 ≤ j, 0 ≤ i, i ≤ j, j ≤ n→i(# vals) + i ⊦ rk = r -- _length, (rk ∈ putArray(vals, r, i, addarray(r, ty, j, st)) ↔ rk = r -- _length ∨ rk ∈ addarray(r, ty, mklist(initial_value(ty), i→n(i)) + vals, st)) ∧ (putArray(vals, r, i, addarray(r, ty, j, st))[rk]) = (addarray(r, ty, mklist(initial_value(ty), i→n(i)) + vals, st)[r -- _length, intval(j)][rk])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 222:
0 ≤ n→i(# vals) + i, 0 ≤ j, 0 ≤ i, i ≤ j, j ≤ n→i(# vals) + i ⊦ rk = r -- _length, (rk ∈ putArray(vals, r, i, addarray(r, ty, j, st)) ↔ rk ∈ addarray(r, ty, mklist(initial_value(ty), i→n(i)) + vals, st)) ∧ (putArray(vals, r, i, addarray(r, ty, j, st))[rk]) = (addarray(r, ty, mklist(initial_value(ty), i→n(i)) + vals, st)[rk])

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ rk ≠ rk0 → (st[rk0, val][rk]) = st[rk]])]]