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Proof step 85 from proof putarray-addarray-01 (previous step)

0 < i0, 0 ≤ i0 + i + n→i(# vals), 0 ≤ i0 + n→i(# vals), 0 ≤ i, i1 < n→i(# vals) + i, i ≤ i1, 0 ≤ i1, 0 < n→i(# vals) + i ⊦ vals[i→n(i1 - i)] = (addarray(r, ty, mklist(initial_value(ty), i→n(i)) + vals + mklist(initial_value(ty), i→n(i0)), st)[r -- i1 ']), vals = []

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 84:
i1 = i2 + i, 0 < i0, 0 ≤ i0 + i + n→i(# vals), 0 ≤ i0 + n→i(# vals), 0 ≤ i, i1 < n→i(# vals) + i, i ≤ i1, 0 ≤ i1, 0 < n→i(# vals) + i ⊦ vals[i→n(i2)] = (addarray(r, ty, mklist(initial_value(ty), i→n(i)) + vals + mklist(initial_value(ty), i→n(i0)), st)[r -- i1 ']), vals = []

Rule argument

[speclemmaarg: ,i0 = i - j ↔ i = i0 + j ,[i, j, i0] → [i1, i, i2] ,T ,int-abs , ,elim-sub ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPELIM : ⊦ i0 = i - j ↔ i = i0 + j])], [EXTRATERMS : (i1, i, i2)]]