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Proof step 34 from proof putarray-addarray-one (previous step)

r0 -- i ' ∈ addarray(r0, ty, n→i(# vals) + 1, st) ∨ ¬ i ≤ 0 ∧ ¬ n→i(# vals) < i ↔ r0 -- i ' ∈ addarray(r0, ty, refval(jvmref) ' + vals, st), is_reftype(ty) ⊦ (putArray(vals, r0, 1, addarray(r0, ty, n→i(# vals) + 1, st))[r0 -- i ']) = (addarray(r0, ty, refval(jvmref) ' + vals, st)[r0 -- i '])

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 8:
⊦ i ≤ j ∧ j < i + n→i(# vals) → (putArray(vals, r, i, st)[r -- j ']) = vals[i→n(j - i)]
Proof step 26:
¬ (1 ≤ i ∧ i < 1 + n→i(# vals)), r0 -- i ' ∈ addarray(r0, ty, n→i(# vals) + 1, st) ∨ ¬ i ≤ 0 ∧ ¬ n→i(# vals) < i ↔ r0 -- i ' ∈ addarray(r0, ty, refval(jvmref) ' + vals, st), is_reftype(ty) ⊦ (putArray(vals, r0, 1, addarray(r0, ty, n→i(# vals) + 1, st))[r0 -- i ']) = (addarray(r0, ty, refval(jvmref) ' + vals, st)[r0 -- i '])
Proof step 33:
1 ≤ i ∧ i < 1 + n→i(# vals), r0 -- i ' ∈ addarray(r0, ty, n→i(# vals) + 1, st) ∨ ¬ i ≤ 0 ∧ ¬ n→i(# vals) < i ↔ r0 -- i ' ∈ addarray(r0, ty, refval(jvmref) ' + vals, st), is_reftype(ty) ⊦ vals[i→n(i - 1)] = (addarray(r0, ty, refval(jvmref) ' + vals, st)[r0 -- i '])

Rule argument

[speclemmaarg: , i ≤ j ∧ j < i + n→i(# vals) → (putArray(vals, r, i, st)[r -- j ']) = vals[i→n(j - i)] ,[j, st, i, r, vals] → [i, addarray(r0, ty, n→i(# vals) + 1, st), 1, r0, vals] ,F ,storearrays , ,putArray-at-in ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (i, addarray(r0, ty, n→i(# vals) + 1, st), 1, r0, vals)]]