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Proof step 53 from proof putarray-addarray-one (previous step)

¬ r ≠ r0, r0 -- sk ∈ addarray(r, ty, n→i(# vals) + 1, st) ∨ r0 = r ∧ ¬ is_fskey(sk) ∧ ¬ sk .index ≤ 0 ∧ ¬ n→i(# vals) < sk .index ↔ r0 -- sk ∈ addarray(r, ty, refval(jvmref) ' + vals, st), is_reftype(ty) ⊦ (putArray(vals, r, 1, addarray(r, ty, n→i(# vals) + 1, st))[r0 -- sk]) = (addarray(r, ty, refval(jvmref) ' + vals, st)[r0 -- sk])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 52:
r0 -- sk ∈ addarray(r0, ty, n→i(# vals) + 1, st) ∨ ¬ is_fskey(sk) ∧ ¬ sk .index ≤ 0 ∧ ¬ n→i(# vals) < sk .index ↔ r0 -- sk ∈ addarray(r0, ty, refval(jvmref) ' + vals, st), is_reftype(ty) ⊦ (putArray(vals, r0, 1, addarray(r0, ty, n→i(# vals) + 1, st))[r0 -- sk]) = (addarray(r0, ty, refval(jvmref) ' + vals, st)[r0 -- sk])

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]