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Proof step 107 from proof putarray-addarray-override (previous step)

i0 < 0 ∨ n→i(# (firstn(i→n(i), vals0) + vals + restn(i→n(i) + # vals, vals0))) ≤ i0, 0 ≤ i, i + n→i(# vals) ≤ n→i(# vals0) ⊦ (putArray(vals, r0, i, addarray(r0, ty, vals0, st))[r0 -- i0 ']) = st[r0 -- i0 '], ¬ i0 < 0 ∧ ¬ i + n→i(# vals) + n→i(# restn(i→n(i) + # vals, vals0)) ≤ i0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 106:
0 ≤ i, i + n→i(# vals) ≤ n→i(# vals0), i0 < 0 ∨ i + n→i(# vals) + n→i(# restn(i→n(i) + # vals, vals0)) ≤ i0 ⊦ (putArray(vals, r0, i, addarray(r0, ty, vals0, st))[r0 -- i0 ']) = st[r0 -- i0 '], ¬ i0 < 0 ∧ ¬ i + n→i(# vals) + n→i(# restn(i→n(i) + # vals, vals0)) ≤ i0

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ m + n = n + m], [CSIMPSEQ : ⊦ (m + n0) + n1 = m + n0 + n1], [CSIMPSEQ : ⊦ 0 ≤ i → n→i(i→n(i)) = i], [CSIMPSEQ : ⊦ n→i(m + n) = n→i(m) + n→i(n)], [CSIMPSEQ : ⊦ (vals + vals0) + vals1 = vals + vals0 + vals1], [CSIMPSEQ : ⊦ # firstn(n, vals) = n], [CSIMPSEQ : ⊦ # (vals + vals0) = # vals + # vals0])]]