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Proof step 135 from proof putarray-addarray-override (previous step)

0 ≤ i, i→n(i) < # vals0, # vals + i→n(i) ≤ # vals0, # vals + i→n(i) + n0 < # vals0, 0 ≤ (n→i(n0) + n→i(# vals)) + i, # vals + i→n(i) + n0 < # vals0, 0 ≤ i + n→i(# vals) ⊦ vals0 = [], vals0[# vals + i→n(i) + n0] = (restn(# vals + i→n(i), vals0)[n0])

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 134:
⊦ m + n < # vals → (restn(m, vals)[n]) = vals[m + n]

Rule argument

[speclemmaarg: ,m + n < # vals → (restn(m, vals)[n]) = vals[m + n] ,[n, vals, m] → [n0, vals0, # vals + i→n(i)] ,F ,list-del ,javavalues ,restn-at ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ (m + n0) + n1 = m + n0 + n1], [CSIMPSEQ : ⊦ m + n = n + m])], [EXTRATERMS : (n0, vals0, # vals + i→n(i))]]