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Proof step 14 from proof putarray-addarray-override (previous step)

0 ≤ i + n→i(# vals), i→n(i) + # vals ≤ # vals0, 0 ≤ i, i→n(i) + # vals ≤ i→n(i0), 0 ≤ i0, # vals0 ≤ i→n(i0), i0 < n→i(# vals0) ⊦ vals0 = [], r -- i0 ' ∈ st

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 13:
0 ≤ i ⊦ ((* m)) ≤ i→n(i) ↔ n→i(m) ≤ i

Rule argument

[speclemmaarg: 0 ≤ i ,((* m)) ≤ i→n(i) ↔ n→i(m) ≤ i ,[i, m] → [i0, # vals0] ,F ,intnat , ,num-i2n-le-02 ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ i < j → (¬ ¬ j ≤ i ↔ false)])], [EXTRATERMS : (i0, # vals0)]]