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Proof step 156 from proof putarray-addarray-override (previous step)

0 ≤ i, i→n(i0) = n + i→n(i), i→n(i) < # vals0, 0 ≤ i, i0 < n→i(# vals0), 0 ≤ i0, i→n(i) + # vals ≤ # vals0, i ≤ i0 ⊦ vals0 = [], (putArray(vals, r0, i, addarray(r0, ty, vals0, st))[r0 -- i0 ']) = (vals + restn(i→n(i) + # vals, vals0))[n]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 155:
i→n(i0) = n + i→n(i), i ≤ i0, i→n(i) + # vals ≤ # vals0, 0 ≤ i0, i0 < n→i(# vals0), 0 ≤ i, i→n(i) < # vals0 ⊦ (putArray(vals, r0, i, addarray(r0, ty, vals0, st))[r0 -- i0 ']) = (vals + restn(i→n(i) + # vals, vals0))[n], vals0 = []

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ # vals = 0 ↔ vals = []], [CSIMPFORWARD : ⊦ m < n → n ≠ 0])]]