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Proof step 18 from proof putarray-addarray-override (previous step)

i ≤ i0 ∧ i0 < i + n→i(# vals), # vals0 ≤ i→n(i0), 0 ≤ i0, i→n(i) + # vals ≤ i→n(i0), 0 ≤ i, i→n(i) + # vals ≤ # vals0, 0 ≤ i + n→i(# vals) ⊦ r -- i0 ' ∈ st

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 17:
0 ≤ i + n→i(# vals), i→n(i) + # vals ≤ # vals0, 0 ≤ i, i→n(i) + # vals ≤ i→n(i0), 0 ≤ i0, # vals0 ≤ i→n(i0), i0 < i + n→i(# vals), i ≤ i0, 0 < i + n→i(# vals) ⊦ vals = [], r -- i0 ' ∈ st

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ i + j = j + i], [CSIMPSEQ : ⊦ i + j + i0 = (i + j) + i0], [CSIMPSEQ : ⊦ # vals = 0 ↔ vals = []], [CSIMPSEQ : ⊦ 0 < n ↔ n ≠ 0], [CSIMPSEQ : 0 ≤ i ⊦ ((* i)) < n→i(n) ↔ i→n(i) < n], [CSIMPSEQ : ⊦ i < i + j ↔ 0 < j], [CSIMPFORWARD : ⊦ i ≤ j ∧ j < j0 → i < j0], [CSIMPSEQ : ⊦ m + n = n + m])]]