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Proof step 186 from proof putarray-addarray-override (previous step)

i→n(i0) < # firstn(i→n(i), vals0), 0 ≤ i, i + n→i(# vals) ≤ n→i(# vals0), i0 < i + n→i(# vals) + n→i(# restn(i→n(i) + # vals, vals0)), 0 ≤ i0, 0 < i + n→i(# vals) + n→i(# restn(i→n(i) + # vals, vals0)) ⊦ (putArray(vals, r0, i, addarray(r0, ty, vals0, st))[r0 -- i0 ']) = (firstn(i→n(i), vals0)[i→n(i0)])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 185:
0 ≤ i, i + n→i(# vals) ≤ n→i(# vals0), i0 < i + n→i(# vals) + n→i(# restn(i→n(i) + # vals, vals0)), 0 ≤ i0, 0 < i + n→i(# vals) + n→i(# restn(i→n(i) + # vals, vals0)), i0 < i, 0 < i ⊦ (putArray(vals, r0, i, addarray(r0, ty, vals0, st))[r0 -- i0 ']) = (firstn(i→n(i), vals0)[i→n(i0)])

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPFORWARD : ⊦ i < j ∧ 0 ≤ i → 0 < j], [CSIMPSEQ : ⊦ 0 ≤ i → abs(i) = i], [CSIMPSEQ : ⊦ i→n(i) < i→n(j) ↔ abs(i) < abs(j)], [CSIMPSEQ : ⊦ # firstn(n, vals) = n])]]