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Proof step 200 from proof putarray-addarray-override (previous step)

¬ i→n(i) + # vals ≤ # vals0, fs ' = _length, i + n→i(# vals) ≤ n→i(# vals0), 0 ≤ i ⊦ n→i(# vals0) = i + n→i(# vals) + n→i(# restn(i→n(i) + # vals, vals0))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 199:
fs ' = _length, # vals0 < i→n(i) + # vals, 0 ≤ i, i + n→i(# vals) ≤ n→i(# vals0) ⊦ n→i(# vals0) = i + n→i(# vals) + n→i(# restn(i→n(i) + # vals, vals0))

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ m < n → n ≠ 0], [CSIMPFORWARD : ⊦ m < n → n ≠ 0], [CSIMPSEQ : ⊦ ¬ m ≤ n ↔ n < m])]]