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Proof step 202 from proof putarray-addarray-override (previous step)

0 ≤ i, i + n→i(# vals) ≤ n→i(# vals0) ⊦ fs ' ≠ _length, (addarray(r0, ty, vals0, st)[r0 -- fs ']) = (addarray(r0, ty, firstn(i→n(i), vals0) + vals + restn(i→n(i) + # vals, vals0), st)[r0 -- fs '])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 196:
⊦ (addarray(r, ty, vals, st)[r -- _length]) = intval(n→i(# vals))
Proof step 201:
fs ' = _length, i + n→i(# vals) ≤ n→i(# vals0), 0 ≤ i ⊦ n→i(# vals0) = i + n→i(# vals) + n→i(# restn(i→n(i) + # vals, vals0))

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ intval(i) = intval(i0) ↔ i = i0], [CSIMPSEQ : ⊦ m + n = n + m], [CSIMPSEQ : ⊦ (m + n0) + n1 = m + n0 + n1], [CSIMPSEQ : ⊦ 0 ≤ i → n→i(i→n(i)) = i], [CSIMPSEQ : ⊦ n→i(m + n) = n→i(m) + n→i(n)], [CSIMPSEQ : ⊦ (vals + vals0) + vals1 = vals + vals0 + vals1], [CSIMPSEQ : ⊦ # firstn(n, vals) = n], [CSIMPSEQ : ⊦ # (vals + vals0) = # vals + # vals0])]]