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Proof step 209 from proof putarray-addarray-override (previous step)

0 ≤ i, i + n→i(# vals) ≤ n→i(# vals0), is_fskey(sk) ⊦ (addarray(r0, ty, vals0, st)[r0 -- sk]) = (addarray(r0, ty, firstn(i→n(i), vals0) + vals + restn(i→n(i) + # vals, vals0), st)[r0 -- sk])

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 194:
⊦ is_fskey(sk) ↔ (∃ fs. sk = fs ')
Proof step 208:
0 ≤ i, i + n→i(# vals) ≤ n→i(# vals0), ∃ fs. sk = fs ' ⊦ (addarray(r0, ty, vals0, st)[r0 -- sk]) = (addarray(r0, ty, firstn(i→n(i), vals0) + vals + restn(i→n(i) + # vals, vals0), st)[r0 -- sk])

Rule argument

[speclemmaarg: ,is_fskey(sk) ↔ (∃ fs. sk = fs ') ,[sk] → [sk] ,F ,storekey , ,ex-03 ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (sk)]]