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Proof step 212 from proof putarray-addarray-override (previous step)

¬ r ≠ r0, 0 ≤ i, i + n→i(# vals) ≤ n→i(# vals0) ⊦ (putArray(vals, r, i, addarray(r, ty, vals0, st))[r0 -- sk]) = (addarray(r, ty, firstn(i→n(i), vals0) + vals + restn(i→n(i) + # vals, vals0), st)[r0 -- sk])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 211:
0 ≤ i, i + n→i(# vals) ≤ n→i(# vals0) ⊦ (putArray(vals, r0, i, addarray(r0, ty, vals0, st))[r0 -- sk]) = (addarray(r0, ty, firstn(i→n(i), vals0) + vals + restn(i→n(i) + # vals, vals0), st)[r0 -- sk])

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]