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Proof step 219 from proof putarray-addarray-override (conclusion)

⊦ 0 ≤ i ∧ i + n→i(# vals) ≤ n→i(# vals0) → putArray(vals, r, i, addarray(r, ty, vals0, st)) = addarray(r, ty, firstn(i→n(i), vals0) + vals + restn(i→n(i) + # vals, vals0), st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 218:
i + n→i(# vals) ≤ n→i(# vals0), 0 ≤ i ⊦ putArray(vals, r, i, addarray(r, ty, vals0, st)) = addarray(r, ty, firstn(i→n(i), vals0) + vals + restn(i→n(i) + # vals, vals0), st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPFORWARD : ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j])]]