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Proof step 95 from proof putarray-addarray-override (previous step)

¬ (0 ≤ i0 ∧ i0 < n→i(# vals0)), i0 < i ∨ n→i(# vals) + i ≤ i0, 0 ≤ i, i + n→i(# vals) ≤ n→i(# vals0), i0 < 0 ∨ i + n→i(# vals) + n→i(# restn(i→n(i) + # vals, vals0)) ≤ i0 ⊦ (addarray(r0, ty, vals0, st)[r0 -- i0 ']) = st[r0 -- i0 '], ¬ i0 < 0 ∧ ¬ i + n→i(# vals) + n→i(# restn(i→n(i) + # vals, vals0)) ≤ i0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 94:
0 ≤ i, i + n→i(# vals) ≤ n→i(# vals0), i0 < i ∨ n→i(# vals) + i ≤ i0, i0 < 0 ∨ i + n→i(# vals) + n→i(# restn(i→n(i) + # vals, vals0)) ≤ i0 ⊦ (addarray(r0, ty, vals0, st)[r0 -- i0 ']) = st[r0 -- i0 '], ¬ i0 < 0 ∧ ¬ i + n→i(# vals) + n→i(# restn(i→n(i) + # vals, vals0)) ≤ i0, ¬ i0 < 0 ∧ ¬ n→i(# vals0) ≤ i0

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ ¬ i < j ↔ j ≤ i], [CSIMPSEQ : ⊦ ¬ i ≤ j ↔ j < i], [CSIMPSEQ : ⊦ i + j = j + i])]]