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Proof step 2 from proof putarray-addarray (previous step)

0 ≤ i, ∀ st, val, r, j, i, vals0. # vals0 < # [] → ( 0 ≤ i ∧ 0 ≤ j ∧ i ≤ j + n→i(# vals0) ∧ j ≤ i ∧ 0 ≤ j + n→i(# vals0) → putArray(vals0, r, j, addarray(r, val, i, st)) = addarray(r, mklist(val, i→n(j)) + vals0, 0, st)) ⊦ addarray(r, val, i, st) = addarray(r, mklist(val, i→n(i)), 0, st)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 1:
⊦ addarray(r, mklist(val, n), 0, st) = addarray(r, val, n→i(n), st)

Rule argument

[crewrite-arg: addarray-mklist-02 , F , [st, n, val, r] → [st, i→n(i), val, r] ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ 0 ≤ i → n→i(i→n(i)) = i])], [EXTRATERMS : (st, i→n(i), val, r)]]