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Proof step 26 from proof putarray-addarray (conclusion)

⊦ 0 ≤ j ∧ j ≤ i ∧ i ≤ j + n→i(# vals) → putArray(vals, r, j, addarray(r, val, i, st)) = addarray(r, mklist(val, i→n(j)) + vals, 0, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 25:
0 ≤ i, 0 ≤ j, i ≤ j + n→i(# vals), j ≤ i, 0 ≤ j + n→i(# vals) ⊦ putArray(vals, r, j, addarray(r, val, i, st)) = addarray(r, mklist(val, i→n(j)) + vals, 0, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ i + j = j + i], [CSIMPSEQ : ⊦ i + j + i0 = (i + j) + i0], [CSIMPSEQ : ⊦ 0 ≤ n→i(n)], [CSIMPSEQ : ⊦ i ≤ i + j ↔ 0 ≤ j], [CSIMPFORWARD : ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j], [CSIMPFORWARD : ⊦ j ≤ j0 ∧ j0 ≤ j1 → j ≤ j1])]]