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Proof step 10 from proof putbytearray-addarray-override (previous step)

# vals1 = 1 + # bytes0, ∀ vals, vals2, r0, st0. # vals2 = # bytes0 → putByteArray(bytes0, r0, n→i(# vals), addarray(r0, byte_type, vals + vals2, st0)) = addarray(r0, byte_type, vals + mkjavavalues(bytes0), st0) ⊦ vals1 = [], putByteArray(bytes0, r, n→i(# vals0) + 1, addarray(r, byte_type, vals0 + vals1[0, byteval(by)], st)) = addarray(r, byte_type, vals0 + byteval(by) ' + mkjavavalues(bytes0), st)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 5:
⊦ vals ≠ [] → vals[0, val] = val ' + vals .rest
Proof step 9:
vals1 ≠ [], # vals1 = 1 + # bytes0, ∀ vals, vals2, r0, st0. # vals2 = # bytes0 → putByteArray(bytes0, r0, n→i(# vals), addarray(r0, byte_type, vals + vals2, st0)) = addarray(r0, byte_type, vals + mkjavavalues(bytes0), st0) ⊦ vals1 = [], putByteArray(bytes0, r, n→i(# vals0) + 1, addarray(r, byte_type, vals0 + byteval(by) ' + vals1 .rest, st)) = addarray(r, byte_type, vals0 + byteval(by) ' + mkjavavalues(bytes0), st)

Rule argument

[speclemmaarg: ,vals ≠ [] → vals[0, val] = val ' + vals .rest ,[val, vals] → [byteval(by), vals1] ,F ,list-del ,javavalues ,put-zero-01 ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (byteval(by), vals1)]]