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Proof step 12 from proof shift-1dim-01 (previous step)

true, ∀ val, sk, st, val0, r0, r, i0. i→n(i0) < i→n(i) → (true → r = r0 ∨ (addarray(r, val0, i0, st)[r0 -- sk, val]) = addarray(r, val0, i0, st[r0 -- sk, val])) ⊦ r = r0 ∨ (addarray(r, val0, i, st)[r0 -- sk, val]) = addarray(r, val0, i, st[r0 -- sk, val])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 11:
∀ val, sk, st, val0, r0, r, i0. i→n(i0) < i→n(i) → (true → r = r0 ∨ (addarray(r, val0, i0, st)[r0 -- sk, val]) = addarray(r, val0, i0, st[r0 -- sk, val])) ⊦ (addarray(r, val0, i, st)[r0 -- sk, val]) = addarray(r, val0, i, st[r0 -- sk, val]), r = r0

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]