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Proof step 9 from proof shift-1init-01 (conclusion)

⊦ r ≠ r0 → (addarray(r, vals, j, st)[r0 -- sk, val]) = addarray(r, vals, j, st[r0 -- sk, val])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 8:
⊦ r = r0, (addarray(r, vals, j, st)[r0 -- sk, val]) = addarray(r, vals, j, st[r0 -- sk, val])

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]