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Proof step 2 from proof store-1init (conclusion)

⊦ j ≤ i ∧ i < j + n→i(# vals) → ((addarray(r, vals, j, st)[r -- i ']) = (addarray(r, vals, j, st0)[r -- i ']) ↔ true)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 1:
⊦ j ≤ i ∧ i < j + n→i(# vals) → (addarray(r, vals, j, st)[r -- i ']) = vals[i→n(i - j)]

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ i + j = j + i], [CSIMPSEQ : ⊦ i + j + i0 = (i + j) + i0])]]