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Proof step 16 from proof stsubset-03 (previous step)

st[rk] = st0[rk], newref(rk .ref, st), rk ∈ st, rk ∈ st0, ∀ rk. rk ∈ st → rk ∈ st0 ∧ st[rk] = st0[rk] ⊦ rk .ref = jvmref, st0[rk] = (addarray(rk .ref, ty, i, st0)[rk])

Heuristic elimination applied rule insert elim lemma

And closed the goal!

Rule argument

[speclemmaarg: ,r = rk .ref ∧ sk = rk .key ↔ rk = r -- sk ,[rk, r, sk] → [rk, r, sk] ,T ,refkey , ,elim ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPFORWARD : ⊦ r -- sk ∈ st → r ∈ st], [CSIMPFORWARD : ⊦ newref(r, st) → r ≠ jvmref], [CSIMPSEQ : ⊦ r ∈ st → ¬ newref(r, st)], [CSIMPELIM : ⊦ r = rk .ref ∧ sk = rk .key ↔ rk = r -- sk])], [EXTRATERMS : (rk, r, sk)]]