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Proof step 10 from proof subset-addarray-01 (previous step)

newref(r, st), newref(r, st0), st ⊆ addarray(r, ty, vals, st0), r0 -- sk ∈ st ⊦ r = jvmref, r0 -- sk ∈ st0 ∧ st[r0 -- sk] = st0[r0 -- sk]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
newref(r, st), newref(r, st0), st ⊆ addarray(r, ty, vals, st0), r0 -- sk ∈ st, r0 ∈ st ⊦ r = jvmref, r0 -- sk ∈ st0 ∧ st[r0 -- sk] = st0[r0 -- sk]

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPFORWARD : ⊦ r -- sk ∈ st → r ∈ st])]]