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Proof step 8 from proof subset-addarray-01 (previous step)

newref(r, st), newref(r, st0), ∀ rk. rk ∈ st → rk ∈ addarray(r, ty, vals, st0) ∧ st[rk] = (addarray(r, ty, vals, st0)[rk]), r0 -- sk ∈ st, r0 ∈ st ⊦ r = jvmref, r0 -- sk ∈ st0 ∧ st[r0 -- sk] = st0[r0 -- sk]

User applied rule all left

And obtained the following new goals

Proof step 7:
newref(r, st), newref(r, st0), r0 -- sk ∈ st → r0 -- sk ∈ addarray(r, ty, vals, st0) ∧ st[r0 -- sk] = (addarray(r, ty, vals, st0)[r0 -- sk]), ∀ rk. rk ∈ st → rk ∈ addarray(r, ty, vals, st0) ∧ st[rk] = (addarray(r, ty, vals, st0)[rk]), r0 -- sk ∈ st, r0 ∈ st ⊦ r = jvmref, r0 -- sk ∈ st0 ∧ st[r0 -- sk] = st0[r0 -- sk]

Rule argument

[EXRARG : pos: left 3, [extquanttermlist: (r0 -- sk)abort:F, discard:F, computed:T]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (r0 -- sk)]]