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Proof step 29 from proof switch-array (previous step)

vals ≠ [], ∀ st, vals0, ty0, ty, r0, r, vals1. # vals1 < # vals → (true → r = r0 ∨ addarray(r, ty, vals1, addarray(r0, ty0, vals0, st)) = addarray(r0, ty0, vals0, addarray(r, ty, vals1, st))) ⊦ (addarray(r, ty, vals .butlast, addarray(r0, ty0, vals0, st))[r -- n→i((# vals) -1) ', vals .last][r -- _length, intval(n→i(# vals))]) = addarray(r0, ty0, vals0, addarray(r, ty, vals, st)), r = r0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 28:
∀ st, vals0, ty0, ty, r0, r, vals1. # vals1 < # vals → (true → r = r0 ∨ addarray(r, ty, vals1, addarray(r0, ty0, vals0, st)) = addarray(r0, ty0, vals0, addarray(r, ty, vals1, st))) ⊦ r = r0, vals = [], (addarray(r, ty, vals .butlast, addarray(r0, ty0, vals0, st))[r -- n→i(# vals - 1) ', vals .last][r -- _length, intval(n→i(# vals))]) = addarray(r0, ty0, vals0, addarray(r, ty, vals, st))

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ n -1 = n - 1])]]