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Proof step 20 from proof union-addarray-rew (previous step)

∃ fs. sk = fs ', newref(r0, st), newref(r0, st0) ⊦ r0 = jvmref, (r0 -- sk ∈ addarray(r0, ty, vals, st ∪ st0) ↔ r0 -- sk ∈ st ∨ r0 -- sk ∈ addarray(r0, ty, vals, st0)) ∧ (addarray(r0, ty, vals, st ∪ st0)[r0 -- sk]) = (st ∪ addarray(r0, ty, vals, st0))[r0 -- sk], sk ≠ _type ∧ sk ≠ _length

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 19:
newref(r0, st), newref(r0, st0) ⊦ r0 = jvmref, (r0 -- fs ' ∈ addarray(r0, ty, vals, st ∪ st0) ↔ r0 -- fs ' ∈ st ∨ r0 -- fs ' ∈ addarray(r0, ty, vals, st0)) ∧ (addarray(r0, ty, vals, st ∪ st0)[r0 -- fs ']) = (st ∪ addarray(r0, ty, vals, st0))[r0 -- fs '], fs ' ≠ _type ∧ fs ' ≠ _length

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]