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Proof step 67 from proof union-addarray-rew (previous step)

newref(r0, st), newref(r0, st0), is_indexkey(sk), sk .index < 0 ∨ n→i(# vals) ≤ sk .index ⊦ r0 = jvmref, (r0 -- sk ∈ addarray(r0, ty, vals, st0) → r0 -- sk ∈ st ∨ r0 -- sk ∈ st0) ∧ (st ∪ st0)[r0 -- sk] = (st ∪ addarray(r0, ty, vals, st0))[r0 -- sk]

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 66:
sk = i ', newref(r0, st), newref(r0, st0), is_indexkey(sk), i < 0 ∨ n→i(# vals) ≤ i ⊦ r0 = jvmref, (r0 -- sk ∈ addarray(r0, ty, vals, st0) → r0 -- sk ∈ st ∨ r0 -- sk ∈ st0) ∧ (st ∪ st0)[r0 -- sk] = (st ∪ addarray(r0, ty, vals, st0))[r0 -- sk]

Rule argument

[speclemmaarg: ,is_indexkey(sk) → (i = sk .index ↔ sk = i ') ,[sk, i] → [sk, i] ,T ,storekey , ,elim-04 ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPELIM : ⊦ is_indexkey(sk) → (i = sk .index ↔ sk = i ')])], [EXTRATERMS : (sk, i)]]