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Proof step 5 from proof validref-addarray (previous step)

⊦ r1 = r0, is_obj(r1, addarray(r0, ty, vals, st)) ∨ is_array(r1, addarray(r0, ty, vals, st)) ↔ is_obj(r1, st) ∨ is_array(r1, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
⊦ r1 ≠ r0 → (is_obj(r1, addarray(r0, ty, vals, st)) ↔ is_obj(r1, st))
Proof step 4:
⊦ r1 ≠ r0 → (is_array(r1, addarray(r0, ty, vals, st)) ↔ is_array(r1, st))

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]