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Proof step 2 from proof zero-1init-02 (conclusion)

⊦ (addarray(r, ty, val ', st)[r -- 0 ']) = val

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 1:
0 ≤ i, i < n→i(# vals) ⊦ (addarray(r, ty, vals, st)[r -- ((* i)) ']) = vals[i→n(i)]

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ (val ')[0] = val], [CSIMPSEQ : ⊦ # val ' = 0 +1])]]