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Proof step 2 from proof zero-1init (conclusion)

⊦ (addarray(r, ty, val + vals, st)[r -- 0 ']) = val

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 1:
⊦ (addarray(r, ty, val ' + vals, st)[r -- 0 ']) = val

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ (vals + vals0) + vals1 = vals + vals0 + vals1], [CSIMPSEQ : ⊦ val + vals = val ' + vals])]]