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Proof step 29 from proof ac-del-01 (previous step)

is_fskey(fv .1), ∀ class1, sk, val0, st, val. (addclass(class1, fis0 + (sk × val0) ', st)[jvmref -- sk, val]) = (addclass(class1, fis0, st)[jvmref -- sk, val]) ⊦ (addclass(class1, (fv ' + fis0) + (sk × val0) ', st)[jvmref -- sk, val]) = (addclass(class1, fv ' + fis0, st)[jvmref -- sk, val])

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 28:
fv = sk0 × val1, is_fskey(sk0), ∀ class1, sk, val0, st, val. (addclass(class1, fis0 + (sk × val0) ', st)[jvmref -- sk, val]) = (addclass(class1, fis0, st)[jvmref -- sk, val]) ⊦ (addclass(class1, (fv ' + fis0) + (sk × val0) ', st)[jvmref -- sk, val]) = (addclass(class1, fv ' + fis0, st)[jvmref -- sk, val])

Rule argument

[speclemmaarg: ,sk = fv .1 ∧ val = fv .2 ↔ fv = sk × val ,[fv, sk, val] → [fv, sk0, val1] ,T ,pair ,fieldinit ,elim ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPELIM : ⊦ sk = fv .1 ∧ val = fv .2 ↔ fv = sk × val])], [EXTRATERMS : (fv, sk0, val1)]]