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Proof step 10 from proof ac-getbar (previous step)

¬ (is_fskey((sk × val) .1) ∧ (sk × val) .1 .fs .class ≠ class), is_fskey(sk), ∀ r, class, st. r = jvmref ∨ getbytearray(r, addclass(class, fis0, st)) = getbytearray(r, st) ⊦ r = jvmref, getbytearray(r, addclass(class, (sk × val) ' + fis0, st)) = getbytearray(r, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
is_fskey(sk), ∀ r, class, st. r = jvmref ∨ getbytearray(r, addclass(class, fis0, st)) = getbytearray(r, st) ⊦ getbytearray(r, addclass(sk .fs .class, (sk × val) ' + fis0, st)) = getbytearray(r, st), r = jvmref

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ ¬ is_indexkey(sk) ↔ is_fskey(sk)], [CSIMPSEQ : ⊦ is_indexkey(sk) → ¬ is_fskey(sk)], [CSIMPSEQ : ⊦ ¬ is_fskey(sk) ↔ is_indexkey(sk)], [CSIMPSEQ : ⊦ (sk × val) .1 = sk])]]