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Proof step 22 from proof ac-in-02 (previous step)

is_indexkey(sk), r -- i ' ∈ addclass(class1, fis0, st), r ∈ addclass(class1, fis0, st), ∀ r0, i0, class, st0. r0 -- i0 ' ∈ addclass(class, fis0, st0) → r0 -- i0 ' ∈ st0 ⊦ r -- i ' ∈ st

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

[EXRARG : pos: left 4, [QUANTTERMLIST : (r, i, class1, st)]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (r, i, class1, st)]]