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Proof step 24 from proof ac-in-02 (previous step)

is_indexkey(fv .1), r -- i ' ∈ addclass(class1, fis0, st), r ∈ addclass(class1, fis0, st), ∀ r0, i0, class, st0. r0 -- i0 ' ∈ addclass(class, fis0, st0) → r0 -- i0 ' ∈ st0 ⊦ r -- i ' ∈ st

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 23:
fv = sk × val, is_indexkey(sk), r -- i ' ∈ addclass(class1, fis0, st), r ∈ addclass(class1, fis0, st), ∀ r0, i0, class, st0. r0 -- i0 ' ∈ addclass(class, fis0, st0) → r0 -- i0 ' ∈ st0 ⊦ r -- i ' ∈ st

Rule argument

[speclemmaarg: ,sk = fv .1 ∧ val = fv .2 ↔ fv = sk × val ,[fv, sk, val] → [fv, sk, val] ,T ,pair ,fieldinit ,elim ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPELIM : ⊦ sk = fv .1 ∧ val = fv .2 ↔ fv = sk × val])], [EXTRATERMS : (fv, sk, val)]]