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Proof step 31 from proof ac-in-03-02 (previous step)

fv = sk0 × val, is_indexkey(sk0), r -- sk ∈ addclass(class1, fis0, st), r ∈ st, ∀ r, sk, class1, st. r -- sk ∈ addclass(class1, fis0, st) ∧ r ∈ st → r = jvmref ∨ r -- sk ∈ st ⊦ r = jvmref, r -- sk ∈ st

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 29:
⊦ r ∈ st → r ∈ addclass(class1, fis, st)
Proof step 30:
r ∈ st, r -- sk ∈ addclass(class1, fis0, st), is_indexkey(sk0), ∀ r, sk, class1, st. r -- sk ∈ addclass(class1, fis0, st) ∧ r ∈ st → r = jvmref ∨ r -- sk ∈ st ⊦ r = jvmref, r -- sk ∈ st

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPFORWARD : ⊦ r -- sk ∈ st → r ∈ st])]]