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Proof step 22 from proof ac-in-03 (previous step)

fv = sk × val, is_fskey(sk), jvmref -- _type ∈ addclass(class1, fis0, st), jvmref ∈ addclass(class1, fis0, st), ∀ class, st0. jvmref -- _type ∈ addclass(class, fis0, st0) ∧ jvmref ∈ addclass(class, fis0, st0) → jvmref -- _type ∈ st0 ⊦ sk .fs .class = class1, jvmref -- _type ∈ st, _type ∈ fv ', _type ∈ fis0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 21:
is_fskey(sk), jvmref -- _type ∈ addclass(class1, fis0, st), jvmref ∈ addclass(class1, fis0, st), ∀ class, st0. jvmref -- _type ∈ addclass(class, fis0, st0) ∧ jvmref ∈ addclass(class, fis0, st0) → jvmref -- _type ∈ st0 ⊦ sk .fs .class = class1, _type = sk, _type ∈ fis0, jvmref -- _type ∈ st

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ sk ∈ (sk0 × val) ' ↔ sk = sk0])]]