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Proof step 27 from proof ac-in-06 (previous step)

is_fskey(fv .1), ∀ class1, class2, ty, fieldvar, st. class1 = class2 ∨ (jvmref -- mkfs(class1, ty, fieldvar) ' ∈ addclass(class2, fis0, st) ↔ jvmref -- mkfs(class1, ty, fieldvar) ' ∈ st) ⊦ class1 = class2, jvmref -- mkfs(class1, ty, fieldvar) ' ∈ addclass(class2, fv ' + fis0, st) ↔ jvmref -- mkfs(class1, ty, fieldvar) ' ∈ st

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 26:
fv = sk × val, is_fskey(sk), ∀ class1, class2, ty, fieldvar, st. class1 = class2 ∨ (jvmref -- mkfs(class1, ty, fieldvar) ' ∈ addclass(class2, fis0, st) ↔ jvmref -- mkfs(class1, ty, fieldvar) ' ∈ st) ⊦ class1 = class2, jvmref -- mkfs(class1, ty, fieldvar) ' ∈ addclass(class2, fv ' + fis0, st) ↔ jvmref -- mkfs(class1, ty, fieldvar) ' ∈ st

Rule argument

[speclemmaarg: ,sk = fv .1 ∧ val = fv .2 ↔ fv = sk × val ,[fv, sk, val] → [fv, sk, val] ,T ,pair ,fieldinit ,elim ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPELIM : ⊦ sk = fv .1 ∧ val = fv .2 ↔ fv = sk × val])], [EXTRATERMS : (fv, sk, val)]]