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Proof step 10 from proof ac-in-08 (previous step)

is_indexkey((sk × val) .1), sk .fs = mkfs(class, ty, fieldvar), r ∈ st, ∀ r, st, class1. r ∈ st → r ∈ addclass(class1, fis0, st) ⊦ r ∈ addclass(class1, fis0, st), class ≠ class1 ∧ ¬ is_indexkey(sk)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
sk .fs = mkfs(class, ty, fieldvar), r ∈ st, is_indexkey(sk), ∀ r, st, class1. r ∈ st → r ∈ addclass(class1, fis0, st) ⊦ r ∈ addclass(class1, fis0, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ (sk × val) .1 = sk])]]