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Proof step 21 from proof ac-in (previous step)

∀ class1, ty, fieldvar, st. jvmref -- mkfs(class1, ty, fieldvar) ' ∈ addclass(class1, fis0, st) ↔ ty = void_type ∧ fieldvar = `initstate' .field ∨ mkfs(class1, ty, fieldvar) ' ∈ fis0 ∨ jvmref -- mkfs(class1, ty, fieldvar) ' ∈ st ⊦ jvmref -- mkfs(class1, ty, fieldvar) ' ∈ addclass(class1, fv ' + fis0, st) ↔ jvmref -- mkfs(class1, ty, fieldvar) ' ∈ st ∨ mkfs(class1, ty, fieldvar) ' ∈ fv ' + fis0 ∨ ty = void_type ∧ fieldvar = `initstate' .field, is_fskey(fv .1) ∧ fv .1 .fs .class ≠ class1

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 20:
fv = sk × val, ∀ class1, ty, fieldvar, st. jvmref -- mkfs(class1, ty, fieldvar) ' ∈ addclass(class1, fis0, st) ↔ ty = void_type ∧ fieldvar = `initstate' .field ∨ mkfs(class1, ty, fieldvar) ' ∈ fis0 ∨ jvmref -- mkfs(class1, ty, fieldvar) ' ∈ st ⊦ jvmref -- mkfs(class1, ty, fieldvar) ' ∈ addclass(class1, fv ' + fis0, st) ↔ jvmref -- mkfs(class1, ty, fieldvar) ' ∈ st ∨ mkfs(class1, ty, fieldvar) ' ∈ fv ' + fis0 ∨ ty = void_type ∧ fieldvar = `initstate' .field, is_fskey(sk) ∧ sk .fs .class ≠ class1

Rule argument

[speclemmaarg: ,sk = fv .1 ∧ val = fv .2 ↔ fv = sk × val ,[fv, sk, val] → [fv, sk, val] ,T ,pair ,fieldinit ,elim ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPELIM : ⊦ sk = fv .1 ∧ val = fv .2 ↔ fv = sk × val])], [EXTRATERMS : (fv, sk, val)]]