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Proof step 37 from proof ac-init (previous step)

is_fskey((sk × val) .1) ∧ (sk × val) .1 .fs .class ≠ class1, is_fskey(sk), ∀ class1, st. mkfs(class1, void_type, `initstate' .field) ' ∈ fis0 ∨ initdone(class1, addclass(class1, fis0, st)) ⊦ mkfs(class1, void_type, `initstate' .field) ' = sk, initdone(class1, addclass(class1, fis0, st)), mkfs(class1, void_type, `initstate' .field) ' ∈ fis0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 36:
is_fskey(sk), ∀ class1, st. mkfs(class1, void_type, `initstate' .field) ' ∈ fis0 ∨ initdone(class1, addclass(class1, fis0, st)) ⊦ mkfs(class1, void_type, `initstate' .field) ' = sk, sk .fs .class = class1, initdone(class1, addclass(class1, fis0, st)), mkfs(class1, void_type, `initstate' .field) ' ∈ fis0

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ (sk × val) .1 = sk])]]