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Proof step 23 from proof ac-isarray (previous step)

is_fskey(fv .1) ∧ fv .1 .fs .class ≠ class1, ∀ r, i, class1, st. is_arrayref(r, i, addclass(class1, fis0, st)) ↔ is_arrayref(r, i, st) ⊦ is_arrayref(r, i, addclass(class1, fis0, st)) ↔ is_arrayref(r, i, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 22:
is_fskey(fv .1), ∀ r, i, class1, st. is_arrayref(r, i, addclass(class1, fis0, st)) ↔ is_arrayref(r, i, st) ⊦ fv .1 .fs .class = class1, is_arrayref(r, i, addclass(class1, fis0, st)) ↔ is_arrayref(r, i, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]