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Proof step 17 from proof ac-lookup-02 (previous step)

is_fskey(sk), ∀ class1, class2, st, ty, fieldvar. class1 = class2 ∨ (addclass(class2, fis0, st)[jvmref -- mkfs(class1, ty, fieldvar) ']) = st[jvmref -- mkfs(class1, ty, fieldvar) '] ⊦ class1 = class2, (addclass(class2, (sk × val) ' + fis0, st)[jvmref -- mkfs(class1, ty, fieldvar) ']) = st[jvmref -- mkfs(class1, ty, fieldvar) ']

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ is_fskey(fv .1) ∧ fv .1 .fs .class ≠ class → addclass(class, fv ' + fis, st) = addclass(class, fis, st)
Proof step 10:
¬ (is_fskey((sk × val) .1) ∧ (sk × val) .1 .fs .class ≠ class2), is_fskey(sk), ∀ class1, class2, st, ty, fieldvar. class1 = class2 ∨ (addclass(class2, fis0, st)[jvmref -- mkfs(class1, ty, fieldvar) ']) = st[jvmref -- mkfs(class1, ty, fieldvar) '] ⊦ class1 = class2, (addclass(class2, (sk × val) ' + fis0, st)[jvmref -- mkfs(class1, ty, fieldvar) ']) = st[jvmref -- mkfs(class1, ty, fieldvar) ']
Proof step 16:
is_fskey((sk × val) .1) ∧ (sk × val) .1 .fs .class ≠ class2, is_fskey(sk), ∀ class1, class2, st, ty, fieldvar. class1 = class2 ∨ (addclass(class2, fis0, st)[jvmref -- mkfs(class1, ty, fieldvar) ']) = st[jvmref -- mkfs(class1, ty, fieldvar) '] ⊦ class1 = class2, (addclass(class2, fis0, st)[jvmref -- mkfs(class1, ty, fieldvar) ']) = st[jvmref -- mkfs(class1, ty, fieldvar) ']

Rule argument

[crewrite-arg: ac-no1 , F , [st, fis, fv, class] → [st, fis0, sk × val, class2] ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (st, fis0, sk × val, class2)]]