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Proof step 10 from proof ac-lookup-03 (previous step)

is_fskey(sk), ∀ class1, st. (addclass(class1, fis0, st)[jvmref -- mkfs(class1, void_type, `initstate' .field) ']) = initval(done) ∨ mkfs(class1, void_type, `initstate' .field) ' ∈ fis0 ⊦ (addclass(class1, (sk × val) ' + fis0, st)[jvmref -- mkfs(class1, void_type, `initstate' .field) ']) = initval(done), mkfs(class1, void_type, `initstate' .field) ' = sk, mkfs(class1, void_type, `initstate' .field) ' ∈ fis0, ¬ is_indexkey(sk) ∧ sk .fs .class ≠ class1

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 9:
sk = fs ', is_fskey(sk), ∀ class1, st. (addclass(class1, fis0, st)[jvmref -- mkfs(class1, void_type, `initstate' .field) ']) = initval(done) ∨ mkfs(class1, void_type, `initstate' .field) ' ∈ fis0 ⊦ (addclass(class1, (sk × val) ' + fis0, st)[jvmref -- mkfs(class1, void_type, `initstate' .field) ']) = initval(done), mkfs(class1, void_type, `initstate' .field) ' = sk, mkfs(class1, void_type, `initstate' .field) ' ∈ fis0, ¬ is_indexkey(sk) ∧ fs .class ≠ class1

Rule argument

[speclemmaarg: ,is_fskey(sk) → (fs = sk .fs ↔ sk = fs ') ,[sk, fs] → [sk, fs] ,T ,storekey , ,elim-03 ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPELIM : ⊦ is_fskey(sk) → (fs = sk .fs ↔ sk = fs ')])], [EXTRATERMS : (sk, fs)]]