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Proof step 14 from proof ac-lookup-05 (previous step)

is_fskey(sk0), is_indexkey(sk), ∀ sk0, class0, st0, r0. ¬ is_fskey(sk0) → (addclass(class0, fis0, st0)[r0 -- sk0]) = st0[r0 -- sk0] ⊦ (addclass(sk0 .fs .class, (sk0 × val) ' + fis0, st)[r -- sk]) = st[r -- sk]

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 13:
sk0 = fs ', is_fskey(sk0), is_indexkey(sk), ∀ sk0, class0, st0, r0. ¬ is_fskey(sk0) → (addclass(class0, fis0, st0)[r0 -- sk0]) = st0[r0 -- sk0] ⊦ (addclass(fs .class, (sk0 × val) ' + fis0, st)[r -- sk]) = st[r -- sk]

Rule argument

[speclemmaarg: ,is_fskey(sk) → (fs = sk .fs ↔ sk = fs ') ,[sk, fs] → [sk0, fs] ,T ,storekey , ,elim-03 ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPELIM : ⊦ is_fskey(sk) → (fs = sk .fs ↔ sk = fs ')])], [EXTRATERMS : (sk0, fs)]]