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Proof step 22 from proof ac-mode (previous step)

is_fskey(fv .1), ∀ class1, st. class1 = `java.lang.Object' .class ∨ (addclass(class1, fis0, st)[_mode]) = st[_mode] ⊦ fv .1 .fs .class = class1, (addclass(class1, fis0, st)[_mode]) = st[_mode], class1 = `java.lang.Object' .class

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 21:
fv = sk × val, is_fskey(sk), ∀ class1, st. class1 = `java.lang.Object' .class ∨ (addclass(class1, fis0, st)[_mode]) = st[_mode] ⊦ sk .fs .class = class1, (addclass(class1, fis0, st)[_mode]) = st[_mode], class1 = `java.lang.Object' .class

Rule argument

[speclemmaarg: ,sk = fv .1 ∧ val = fv .2 ↔ fv = sk × val ,[fv, sk, val] → [fv, sk, val] ,T ,pair ,fieldinit ,elim ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPELIM : ⊦ sk = fv .1 ∧ val = fv .2 ↔ fv = sk × val])], [EXTRATERMS : (fv, sk, val)]]